OpenFile Dialog Box

The OpenFileDialog component displays a dialog box that allows the user to choose a file to open.

The FileName property can be set prior to showing the dialog box. This causes the dialog box to initially display the given filename. In most cases, your applications should set the InitialDirectory, Filter, and FilterIndex properties prior to calling ShowDialog.

The following VB.Net program invites an OpenFile Dialog Box and retrieve the selected filename to a string.

Public Class Form1
	Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

		Dim dlg As New OpenFileDialog
		dlg.ShowDialog()

		If dlg.ShowDialog = Windows.Forms.DialogResult.OK Then
			Dim fileName As String
			fileName = dlg.FileName
			MsgBox(fileName)
		End If

	End Sub
End Class